Kamis, 03 Maret 2016
Berikut soal latihan tentukan:
a)
Alamat subnet mask
b)
Alamat subnet
c)
Alamt broadeast
d)
Jumlah host yang dapat digunakan
Dari alamat sebagai berikut:
1.
198.53.67.0/30
2.
202.151.37,0/26
1.
198.53.67.0/30
Diket 30 : 11111111.11111111.11111111.11111100
·
Subnet mask = 255.255.255.252
·
Jumlah subnet = 2x=26=64
·
Jumlah host P = 2y-2=22-2=4-2=2 host
·
Blok subnet = 256-252=4 berikutnya 4+4=8 dan 8+4=12 jadi
subnet lengkapnya 0,4,8,12
Subnet
|
198.53.67.0
|
198.53.67.4
|
198.53.67.8
|
198.53.67.12
|
Host Pertama
|
198.53.67.1
|
198.53.67.5
|
198.53.67.9
|
198.53.67.13
|
Host Terakhir
|
198.53.67.2
|
198.53.67.6
|
198.53.67.10
|
198.53.67.14
|
Broadcast
|
198.53.67.3
|
198.53.67.7
|
198.53.67.11
|
198.53.67.15
|
a)
Subnet mask =255.255.255.252
b)
Subnet =(198.53.67.0) (198.53.67.4)
(198.53.67.8) (198.53.67.12)
c)
Broadcast =(198.53.67.3) (198.53.67.7)
(198.53.67.11) (198.53.67.15)
d)
Jumlah host yang dapat digunakan [ jumlah host X jumlah subnet]
2 X
64 =128
2.
202.151.37.0/26
Diket 26 :
11111111.11111111.11111111.11000000
·
Subnet mask =255.255.255.192
·
Jumlah subnet
=2x=22=4 subnet
·
Jumlah host P
=2y-2=26-2=64-2=62
·
Blok subnet
=256-192 =64 berikutnya 64+64=128 dan 128+64=192 jadi subnet lengkapnya
0.64.128.192
Subnet
|
202.151.37.0
|
202.151.37.64
|
202.151.37.128
|
202.151.37.192
|
Hoast Pertama
|
202.151.37.1
|
202.151.37.65
|
202.151.37.129
|
202.151.37.193
|
Host Terakhir
|
202.151.37.62
|
202.151.37.126
|
202.151.37.190
|
202.151.37.254
|
Broadcast
|
202.151.37.63
|
202.151.37.127
|
202.151.37.191
|
202.151.37.255
|
a)
Subnet mask =255.255.255.192
b)
Jumlah subnet
=(202.151.37.0) (202.151.37.64) (202.151.37.128) (202.151.37.192)
c)
Broadcast
=(202.151.37.63) (202.151.37.127) (202.151.37.191) (202.151.37.255)
d)
Jumlah host yang dapat digunakan [ jumlah host X jumlah subnet ]
62 X 4 = 248
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